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🛠️ Hydraulic Cylinder Force Calculator

Enter hydraulic pressure (P) and cylinder bore diameter to calculate push force via F=P×A. Pull (retract) force additionally accounts for the piston rod diameter via the annular area.

Force (N)
Force (kgf) Force (lbf) Effective area

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01

Hydraulic Cylinder Force Formula (F = P × A)

The force a hydraulic cylinder can produce is F = P × A, where P is the hydraulic pressure and A is the effective piston area.

When extending (push), the full circular area from the bore (cylinder bore) diameter D applies: A = π × (D/2)².
02

Why is Pull Force Calculated Differently?

When the cylinder retracts (pull), pressure is applied to the opposite chamber, whose area is reduced by the space occupied by the piston rod. So the effective area is the annular area, A = (π/4) × (D² − d²), computed from the bore and rod diameters. The larger the rod diameter (d), the smaller the pull force is relative to the push force.
03

Unit Conversions for Pressure & Diameter

Pressure can be entered in bar (1 bar = 100,000 Pa), psi (1 psi ≈ 6,894.76 Pa), or MPa (1 MPa = 1,000,000 Pa); diameter in mm or in (1 in = 25.4 mm). Results are shown primarily in N (newtons), alongside kgf (÷9.80665) and lbf (×0.224809).

Frequently asked questions

Is push force always greater than pull force?
Yes, at the same pressure, push (extend) force is always greater. Pull force is reduced by the area the rod occupies, so it is always less than or equal to the push force.
What if I don't know the rod diameter?
Check the cylinder manufacturer's catalog/spec sheet for exact bore and rod diameters. As a rough rule of thumb rod diameter is often about 40-70% of bore diameter, but always use the actual product specification for accurate results.
Does this account for friction or seal losses?
No. This calculator computes the theoretical force from F=P×A only, and does not account for seal friction, line pressure drop, etc. Actual output may be a few percent lower.